Three plates of common surface area `A` are connected as shown. The effective capacitance will be

Options

A. `(epsilon_(0)A)/(d)`
B. `(3 epsilon_(0)A)/(d)`
C. `(3)/(2)(epsilon_(0)A)/(d)`
D. `(2epsilon_(0)A)/(d)`

Answer

D

Explanation

The given circuit is equivalent to parallel combination of two identical capacitors, each having capacitance
`C = (epsilon_(0)A)/(d)`. Hence `C_(eq) = 2C = (2epsilon_(0)A)/(d)`