Four plates of equal area `A` are separated by equal distance `d` and are arranged as shown in the figure. The equivalent capacity is

Options

A. `(2epsilon_(0)A)/(d)`
B. `(3epsilon_(0)A)/(d)`
C. `(3epsilon_(0)A)/(d)`
D. `(epsilon_(0)A)/(d)`

Answer

A

Explanation

The given circuit is equivalent to a parallel combination two identical capacitors
Hence equivalent capacitance between `A` and `B` is

`C = (epsilon_(0)A)/(d) + (epsilon_(0)A)/(d)`
`= (2epsilon_(0)A)/(d)`