The lowest resistance which can be obtained by connecting 10 resistors each of `1//10 ohm` is

Options

A. `1//250 Omega`
B. `1//200 Omega`
C. `1//100 Omega`
D. `1//10 Omega`

Answer

C

Explanation

(c ) Lowest resistance will be in the case when all the resistors are connected in parallel
`(1)/(R ) = (1)/(0.1) + (1)/(0.1)`…….10 times
`(1)/(R ) = 10 + 10`……………10 times
`(1)/(R ) = 100` or `R = (1)/(100) Omega`