In the circuit shown in fig the heat produced in the 5 ohm resistor due to the current flowing through it is 10 calories per second.

The heat generated in the 4 ohms resistor is

Options

A. `1 cal//s`
B. `2 cal//s`
C. `3 cal//s`
D. `4 cal//s`

Answer

B

Explanation

(b) `P = e^(2) R implies 10 i^(2) 5 implies i^(2) = (10)/(5) = 2 implies i = sqrt2`
`i_(4) = (i_(5))/(2) implies P_(4) = ((i)/(2))^(2) 4, P_(5) = (i^(2)) 5`
`(P_(4))/(P_(5)) = (1)/(5) implies P_(4) = (P_(5))/(5) = (10)/(4) = 2 cal//s`