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Masses of 3 wires of same metal are in t...

Masses of 3 wires of same metal are in the ratio `1 : 2 : 3` and their lengths are in the ratio `3 : 2 : 1`. The electrical resistances are in ratio

A

`1 : 4 : 9`

B

`9 : 4 : 1`

C

`1 : 2 : 3`

D

`27 : 6 : 1`

Text Solution

Verified by Experts

The correct Answer is:
D

(d) `R prop (l^(2))/(m) implies R_(1) : R_(2) : R_(3) = (l_(1)^(2))/(m_(1)) : (l_(2)^(2))/(m_(2)) : (l_(3)^(2))/(m_(3))`
`implies R_(1) : R_(2) : R_(3) = (9)/(1) : (4)/(2) : (1)/(3) = 27 : 6 : 1`
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