When a `12 Omega` resistor is connected with a moving coil galvanometer, then its deflection reduces form 50 divions to 10 divisions. The ressitance of the galvanometer is

Options

A. `24 Omega`
B. `36 Omega`
C. `48 Omega`
D. `60 Omega`

Answer

C

Explanation

(c ) `i_(g) = (iS)/(S + G) implies 10 = (50 xx 12)/(12 + G) implies 12 + G = 60`
`implies G = 48 Omega`