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In a Wheatstone's brigde all the four ar...

In a Wheatstone's brigde all the four arms have equal resistance `R`. If the resistance of the galvanometer arm is also `R`, the equivalent resistance of the combination as seen b the battery is

A

`(R )/(2)`

B

`R`

C

`2 R`

D

`(R )/(4)`

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The correct Answer is:
To find the equivalent resistance of a Wheatstone bridge where all four arms have equal resistance \( R \) and the galvanometer arm also has resistance \( R \), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Configuration**: In a Wheatstone bridge, we have four resistances arranged in a diamond shape. Let’s label them as follows: - \( R_1 = R \) (top arm) - \( R_2 = R \) (bottom arm) - \( R_3 = R \) (left arm) - \( R_4 = R \) (right arm) - \( R_g = R \) (galvanometer arm) 2. **Check for Balance**: The Wheatstone bridge is balanced when the ratio of the resistances in one branch is equal to the ratio in the other branch. For our case: \[ \frac{R_1}{R_2} = \frac{R_3}{R_4} \] Since all resistances are equal (\( R \)), this condition simplifies to: \[ \frac{R}{R} = \frac{R}{R} \implies 1 = 1 \] Thus, the bridge is balanced. 3. **Effect of Balance**: When the bridge is balanced, no current flows through the galvanometer. Therefore, we can ignore the galvanometer in our calculations, effectively removing it from the circuit. 4. **Redraw the Circuit**: After removing the galvanometer, we are left with two pairs of resistors in parallel: - The top and bottom resistors (\( R_1 \) and \( R_2 \)) are in series, and their total resistance is: \[ R_{top} = R + R = 2R \] - The left and right resistors (\( R_3 \) and \( R_4 \)) are also in series, giving: \[ R_{bottom} = R + R = 2R \] 5. **Calculate the Equivalent Resistance**: Now, we have two resistances \( R_{top} \) and \( R_{bottom} \) in parallel: \[ R_{eq} = \frac{R_{top} \times R_{bottom}}{R_{top} + R_{bottom}} = \frac{2R \times 2R}{2R + 2R} \] Simplifying this: \[ R_{eq} = \frac{4R^2}{4R} = R \] ### Final Answer: The equivalent resistance of the combination as seen by the battery is \( R \). ---

To find the equivalent resistance of a Wheatstone bridge where all four arms have equal resistance \( R \) and the galvanometer arm also has resistance \( R \), we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Configuration**: In a Wheatstone bridge, we have four resistances arranged in a diamond shape. Let’s label them as follows: - \( R_1 = R \) (top arm) - \( R_2 = R \) (bottom arm) ...
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