A glavanometer of `50 Omega` resistance has 25 divisions. A current of `4xx10^(-4)` A gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of `25 V`, it should be connected with a resistance of

Options

A. `2500 Omega` as a shunt
B. `2450 Omega` as a shunt
C. `2550 Omega` in series
D. `2450 Omega` in series

Answer

D

Explanation

(d) Full deflection current `i_(g) = 25 xx 4 xx 10^(-4)`
`= 100 xx 10^(-4) A`
Using `R = (V)/(I_(g)) - G = (25)/(100 xx 10^(-4)) - 50 = 2450 Omega` in series