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When a wire of uniform cross-section a, ...

When a wire of uniform cross-section `a`, length `I` and resistance `R` is bent into a complete circle, resistance between two of diametrically opposite points will be

A

`(R )/(4)`

B

`(R )/(8)`

C

`(4 R)`

D

`(R )/(2)`

Text Solution

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The correct Answer is:
To find the resistance between two diametrically opposite points on a wire of uniform cross-section that has been bent into a complete circle, we can follow these steps: ### Step 1: Understand the initial conditions We have a wire of length \( L \), cross-sectional area \( A \), and resistance \( R \). The resistance \( R \) of the wire is given by the formula: \[ R = \rho \frac{L}{A} \] where \( \rho \) is the resistivity of the material. ### Step 2: Determine the circumference of the circle When the wire is bent into a complete circle, the length of the wire becomes the circumference of the circle: \[ C = 2\pi r \] where \( r \) is the radius of the circle. ### Step 3: Relate the length of the wire to the radius Since the wire was originally of length \( L \), we have: \[ L = 2\pi r \] From this, we can express the radius \( r \): \[ r = \frac{L}{2\pi} \] ### Step 4: Determine the resistance of each semicircle When the wire is bent into a circle, it can be divided into two semicircular sections. Each semicircular section has a length of: \[ \text{Length of each semicircle} = \frac{L}{2} \] The resistance of each semicircular section can be calculated using the resistance formula: \[ R_{\text{semicircle}} = \rho \frac{\frac{L}{2}}{A} = \frac{R}{2} \] Thus, each semicircle has a resistance of \( \frac{R}{2} \). ### Step 5: Calculate the equivalent resistance between two diametrically opposite points The two semicircles are in parallel when considering the resistance between points A and B (the diametrically opposite points). The equivalent resistance \( R_{AB} \) can be calculated using the formula for resistors in parallel: \[ \frac{1}{R_{AB}} = \frac{1}{R_{\text{semicircle}}} + \frac{1}{R_{\text{semicircle}}} \] Substituting \( R_{\text{semicircle}} = \frac{R}{2} \): \[ \frac{1}{R_{AB}} = \frac{1}{\frac{R}{2}} + \frac{1}{\frac{R}{2}} = \frac{2}{R} + \frac{2}{R} = \frac{4}{R} \] Thus, \[ R_{AB} = \frac{R}{4} \] ### Final Answer The resistance between two diametrically opposite points is: \[ R_{AB} = \frac{R}{4} \]

To find the resistance between two diametrically opposite points on a wire of uniform cross-section that has been bent into a complete circle, we can follow these steps: ### Step 1: Understand the initial conditions We have a wire of length \( L \), cross-sectional area \( A \), and resistance \( R \). The resistance \( R \) of the wire is given by the formula: \[ R = \rho \frac{L}{A} \] where \( \rho \) is the resistivity of the material. ...
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