A `5-A` wire can withstand a maximum power of `1W` in circuit. The resistance of the fuse wire is

Options

A. `0.2 Omega`
B. `5 Omega`
C. `0.4 Omega`
D. `0.04 Omega`

Answer

D

Explanation

(d) Power `P = i^(2) R`
`implies R = (P)/(i^(2))`
Given, `P = 1 W, i= 5 A`
`:. R = (1)/((5)^(2)) = 0.04 Omega`