In producing chlorine through electrolysis `100 W` power at `125 V` is being consumed. How much chlorine per min is liberated ? `ECE` of chlorine is `0.367 xx 10^(6) kg//C`

Options

A. `17.6 mg`
B. `21.3 mg`
C. `24.3 mg`
D. `13.6 mg`

Answer

A

Explanation

(a) The mass of a substance deposited or liberated at an electrode is directly proportinal to the quantity of electricity, i.e., charge passed through the electrolyte.
Power consumed in electrolysis, `P = 100 W`
Voltage applied, `V = 125 V`
So, current in solution, `i= (P)/(V) = (100)/(125) = 0.8 A`
According to first law of Faraday, mass liberated at an electrode is directly proportional to change passed through the electrolyte, i.e.,
`m alpha Q implies m = z Q`
Where `z`is a constant called 'electrochemical equivalent' `(ECE)`
Also `Q = i t` ltbgt `:. m = z i t`
Given, `z = 0.367 xx 10^(-6) kg// C`, I = 0.8 A, t = 60 s`
Hence, `m = 0.367 xx 10^(-6) xx 0.8 xx 60`
`= 17.6 xx 10^(-5) kg = 17.6 mg`