In the circuit shown the cells `A` and `B` have negligible resistance. For `V_(A) = 12 V, R_(1) = 500 Omega` and `R = 100 Omega`, the galvanometer `(G)` shows no deflection. The value of `V_(B)` is

Options

A. ` 6 V`
B. ` 4 V`
C. ` 2 V`
D. ` 12 V`

Answer

C

Explanation

(c ) Applying Kirchhoff's law in loop '1'
`500 I + 100 I = 12`
So, `I = (12 xx 10^(-2))/(6) = 2 xx 10^(-2) A`
Hence, `V_(B) = 100 (2 xx 10^(-2)) = 2 V`