The power dissipated in the circuit shown in the figure is 30 watt. The shown in figure is 30 watt. The value of `R` is

Options

A. `20 Omega`
B. `15 Omega`
C. `10 Omega`
D. `30 Omega`

Answer

C

Explanation

(c ) `R_(1) = R = ?`
`R_(2) = 5 Omega, V = 10 V`
and `P = 30 W`
Hence `P = (V_(2))/(R_(1)) + (V_(2))/(R_(2))`
`(10^(2))/(R ) = 30 - (10^(2))/(5)`
`(100)/(R ) = 30 - 20`
`R = 10 Omega`