A carbon resistor of `(47 +- 4.7) k Omega` is to be marked with rings of different colours for its identification. The colour code sequence will be

Options

A. Green - Orange - Voilet - Gold
B. Violet - Yellow - Orange - Silver
C. Yellow- Green - Violet - Gold
D. Yellow - Violet - Orange - Silver

Explanation

To determine the color code for the carbon resistor with a resistance of \( (47 \pm 4.7) \, k\Omega \), we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Resistance Value**:
The resistance value given is \( 47 \, k\Omega \). This can be expressed in ohms as:
\[ 47 \, k\Omega = 47 \times 10^3 \, \Omega = 47000 \, \Omega \]

2. **Determine the Significant Figures**:
The first two digits of the resistance value are 4 and 7. Thus, we will use these digits for the first two color bands.

3. **Assign Colors to the First Two Bands**:
- The first digit (4) corresponds to the color **Yellow**.
- The second digit (7) corresponds to the color **Violet**.

4. **Determine the Multiplier**:
The resistance is multiplied by \( 10^3 \). The exponent here is 3, which corresponds to the color **Orange**.

5. **Determine the Tolerance**:
The tolerance is given as \( \pm 4.7 \, k\Omega \). To find the percentage tolerance:
\[ \text{Percentage Tolerance} = \left(\frac{4.7}{47}\right) \times 100 \approx 10\% \]
A tolerance of \( 10\% \) corresponds to the color **Silver**.

6. **Compile the Color Code**:
Based on the above assignments, the color code for the resistor will be:
- First Band: Yellow (4)
- Second Band: Violet (7)
- Third Band: Orange (multiplier of \( 10^3 \))
- Fourth Band: Silver (tolerance of \( 10\% \))

### Final Color Code Sequence:
The final color code sequence for the resistor is:
**Yellow - Violet - Orange - Silver**

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