The equivalent resistance between the point `P` and `Q` in the network given here is equal to (given `r = (3)/(2) Omega)`

Options

A. `(1)/(2) Omega`
B. `1 Omega`
C. `(3)/(2) Omega`
D. `2 Omega`

Answer

B

Explanation

(b) The given circuit can be simplified as follows :
`R' = (2 r)/(3) = (2)/(3) xx (3)/(2) = Omega`