In the circuit `P != R, ` the reading of the galvanometer is same with switch S open or closed. Then

Options

A. `I_(R) = I_(G)`
B. `I_(P) = I_(G)`
C. `I_(Q) = I_(G)`
D. `I_(Q) = I_(R)`

Answer

A

Explanation

(a) Reading of galvanometer remains same whether switch `S` is open or closed, hence no current will flow through the switch i.e., `R` and `G` will be in series and same current will flow through them. `I_(R) = I_(G)`.