Figure `7.37` shows a network of three resistances. When some potential difference is applied across the network , thermal powers dissipated by `A, B and C` are in the ratio

Options

A. `2 : 3 : 4`
B. `2 : 4 :`
C. `4 : 2 : 3`
D. `3 : 2 : 4`

Answer

C

Explanation

(c ) Thermal power in `A = P_(A) = ((2 i)/(3))^(2) 3R = (4)/(3) i^(2) R`
Theremal power in `B = P_(B) = ((i)/(3))^(2) 6R = (2)/(3) i^(2) R`
Thermal power in `C = PC = i^(2) R`
`implies P_(A) : P_(B) : P_(C) = (4)/(3) : (2)/(3) : 1 = 4 : 2 : 3`