In the diagram find out the current through `2 Omega` `(R_(3))` :

Options

A. 0
B. `3//2 A`
C. `2 A`
D. `9//2 A`

Answer

D

Explanation

(d) Let us consider, `V_(A) = 0 so V_(B) = 0`
`:. V_(C )` volt, `V_(D) = - 6` volt
Hence, `V_(C ) - V_(D) = I_(R)`
`implies 9 = I xx 2 implies I = (9)/(2)`