Home
Class 12
PHYSICS
The magnetic needle of a tangent galvano...

The magnetic needle of a tangent galvanometer is deflected at an angle `30^(@)` due to a magnet. The hoeizontal component of earth's magnetic field `0.34xx10^(-4)T` is along the plane of the coil. The magnetic intensity is

A

`1.96xx10^(-4)T`

B

`1.96xx10^(-5)T`

C

`1.96xx10^(4)T`

D

`1.96xx10^(5)T`

Text Solution

Verified by Experts

The correct Answer is:
B

`B=B_(H) tan theta`
`=0.34xx10^(-4) tan 30^(@) =1.96xx10^(-5)T`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MAGNETISM AND MATTER

    A2Z|Exercise Section D - Chapter End Test|30 Videos
  • MAGNETISM AND MATTER

    A2Z|Exercise AIPMTNEET Questions|26 Videos
  • GEOMETRICAL OPTICS

    A2Z|Exercise Section D - Chapter End Test|30 Videos
  • MOCK TEST

    A2Z|Exercise Mock Test 3|44 Videos

Similar Questions

Explore conceptually related problems

The magnetic needle of a tangent galvanometer is deflected at an angle of 30^@ due to magnet. The horizontal component of earth's magnetic field 0*34xx10^-4T is along the plane of the coil. What is magnetic intensity?

The magnetic needle of tangent galvanometer is deflected at an angle 30^(@) due to a magnet the horizontal component of earths magnetic field is 0.34 xx 10 ^(-4) T along the plane of the coil. Then the magnetic intensity will be

Knowledge Check

  • The angle of dip at a certain place is 30^(@) . If the horizontal component of the earth's magnetic field is H, the intensity of the total magnetic field is

    A
    `H/2`
    B
    `(2H)/sqrt(3)`
    C
    `Hsqrt(2)`
    D
    `Hsqrt(3)`
  • At certain place, the horizontal component of earth's magnetic field is 3.0G and the angle dip at the place is 30^(@) . The magnetic field of earth at that location

    A
    4.5G
    B
    5.1G
    C
    3.5G
    D
    6.0G
  • The horizontal component of the earth's magnetic field is 0.22 Gauss and total magnetic field is 0.4 Gauss. The angle of dip. Is

    A
    `tan^(-1)(1)`
    B
    `tan^(-1)(oo)`
    C
    `tan^(-1)(1.518)`
    D
    `tan^(-1)(pi)`
  • Similar Questions

    Explore conceptually related problems

    The horizontal component of the earth's magnetic field is 3.6 xx 10^(-5) T where the dip is 60^@ . Find the magnitude of the earth's magnetic field.

    Calculate earth's magnetic field at a place where angle of dip delta is 60^(@) and horizontal component of earth's magnetic field is 0.3 G

    At a certain place the angle of dip is 30^@ and the horizontal component of earth's magnetic field is 3.2 xx 10^(-5)T . Earth's total magnetic field at the place is

    At a certain place the angle of dip is 30^(@) and the horizontal component of earth's magnetic field is 0.50 oersted. The earth's total magnetic field is

    A tangent galvanometer has a coil of 25 turns and radius of 15 cm. The horizontal component of the earth's magnetic field is 3xx10^(-5)T . The current required to producea defection of 45^(@) in it, is