Power dissipated in an `L-C-R` series circuit connected to an `AC` source of emf `epsilon` is

Options

A. `(epsilon^(2)R)/([R^(2)+(Lomega-1/(Comega))^(2)])`
B. `(epsilon^(2)sqrt(R^(2)+(Lomega-1/(Comega))^(2)))/R`
C. `(epsilon^(2)[R^(2)+(Lomega-1/(Comega))^(2)])/R`
D. `(epsilon^(2)R)/(sqrt(R^(2)+(Lomega-1/(Comega))^(2)))`

Answer

A

Explanation

Power dissipated in series `L-C-R`.
`P=I_(rms)^(2)R (epsilon_(rms)^(2)R)/(|Z|^(2))=(epsilon^(2)R)/([R^(2)+(omega L-1/(omegaC))^(2)])`