In an `AC` circuit, peak value of voltage is `423` volts. Its effective voltage is

Options

A. `400` volts
B. `323` volts
C. `300` volts
D. `340` volts

Explanation

To find the effective voltage (also known as the root mean square or RMS voltage) from the peak voltage in an AC circuit, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values**:
- The peak voltage \( V_{\text{peak}} \) is given as \( 423 \) volts.

2. **Understand the relationship between peak voltage and effective voltage**:
- The effective voltage (RMS voltage) \( V_{\text{rms}} \) can be calculated using the formula:
\[ V_{\text{rms}} = \frac{V_{\text{peak}}}{\sqrt{2}} \]

3. **Substitute the given peak voltage into the formula**:
- Substitute \( V_{\text{peak}} = 423 \) volts into the formula:
\[ V_{\text{rms}} = \frac{423}{\sqrt{2}} \]

4. **Calculate \( \sqrt{2} \)**:
- The value of \( \sqrt{2} \) is approximately \( 1.414 \).

5. **Perform the division**:
- Now, calculate \( V_{\text{rms}} \):
\[ V_{\text{rms}} = \frac{423}{1.414} \approx 299.7 \text{ volts} \]

6. **Round the result**:
- Rounding \( 299.7 \) volts gives us approximately \( 300 \) volts.

7. **Conclusion**:
- Therefore, the effective voltage (RMS voltage) is approximately \( 300 \) volts.

### Final Answer:
The effective voltage is approximately **300 volts**.

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