For the circuit shown in the figure, the current through the inductor is `0.9A` while the current through the condenser is `0.4 A.` hence the current drawn from the generator is

Options

A. `I=1.13` amp
B. `I=0.9` amp
C. `I=0.5` amp
D. `I=0.6` amp

Answer

C

Explanation

The current drawn by inductance and capacitor will be in opposite phase. Hence, net current drawn by the generator `=I_(L)-I_(C)=0.9-0.4=0.5` amp