In a series LCR circuit, the voltage across the resistance, capacitance and inductance is 10 V each. If the capacitance is short circuited, the voltage across the inductance will be

Options

A. `10 V`
B. `10//sqrt(2)V`
C. `10sqrt(2)V`
D. `20 V`

Answer

B

Explanation

Here `R=X_(L)=X_(C)`(`:'` voltage across them is same)
Total voltage in the circuit,
`V=I[R^(2)+(X_(L)-X_(C))^(2)]^(1//2)`
`IR=10` volt
When capacitor is short circulated,
`I=10/((R^(2)+X_(L)^(2))^(1//2))=10/(sqrt(2)R)`
`:.` Potential drop across inductance
`=IX_(L)=IR=10/(sqrt(2))` volt