When light rays are incident on a prism at an angle of `45^(@)`, the minimum deviation is obtained. If refractive index of the material of prism is `sqrt(2)`, then the angle of prism will be

Options

A. `30^(@)`
B. `40^(@)`
C. `50^(@)`
D. `60^(@)`

Answer

D

Explanation

`(sin.(A+deltam)/(2))/(sin .(A)/(2))=mu, `But` (A+delta_(m))/(2)=i=45^(@)`
So,` (sin 45^(@))/(sin(A//2))=sqrt(2)implies(1)/(2)=sin.(A)/(2)impliesA=60^(@)`