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A ray of monochromatic light is incident...

A ray of monochromatic light is incident on one refracting face of a prism of angle `75^(@)`. It passes through the prism and is incident on the other face at the critical angle. If the refractive index of the material of the prism is `sqrt(2)`, the angle of incidence on the first face of the prism is

A

`30^(@)`

B

`45^(@)`

C

`60^(@)`

D

`0^(@)`

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The correct Answer is:
To solve the problem step by step, we need to determine the angle of incidence on the first face of the prism. Here’s how we can approach it: ### Step 1: Understand the Given Information - The angle of the prism \( A = 75^\circ \) - The refractive index of the prism \( \mu = \sqrt{2} \) - The light ray is incident on the second face of the prism at the critical angle \( C \). ### Step 2: Calculate the Critical Angle The critical angle \( C \) can be calculated using the formula: \[ \sin C = \frac{1}{\mu} \] Substituting the value of \( \mu \): \[ \sin C = \frac{1}{\sqrt{2}} \] Thus, \[ C = \sin^{-1}\left(\frac{1}{\sqrt{2}}\right) = 45^\circ \] ### Step 3: Use the Prism Formula In a prism, the relationship between the angles is given by: \[ A = R_1 + R_2 \] where \( R_1 \) is the angle of refraction at the first face and \( R_2 \) is the angle of refraction at the second face. Since the light exits at the critical angle \( C \), we have: \[ R_2 = C = 45^\circ \] Thus, we can rearrange the equation to find \( R_1 \): \[ R_1 = A - C \] Substituting the known values: \[ R_1 = 75^\circ - 45^\circ = 30^\circ \] ### Step 4: Apply Snell's Law Now, we can apply Snell's law at the first face of the prism: \[ \mu_1 \sin I = \mu_2 \sin R_1 \] Assuming the light is coming from air (where \( \mu_1 = 1 \)) and entering the prism (where \( \mu_2 = \sqrt{2} \)): \[ 1 \cdot \sin I = \sqrt{2} \cdot \sin(30^\circ) \] Since \( \sin(30^\circ) = \frac{1}{2} \), we have: \[ \sin I = \sqrt{2} \cdot \frac{1}{2} = \frac{\sqrt{2}}{2} \] ### Step 5: Calculate the Angle of Incidence Now, we can find the angle \( I \): \[ I = \sin^{-1}\left(\frac{\sqrt{2}}{2}\right) = 45^\circ \] ### Final Answer The angle of incidence on the first face of the prism is \( 45^\circ \). ---

To solve the problem step by step, we need to determine the angle of incidence on the first face of the prism. Here’s how we can approach it: ### Step 1: Understand the Given Information - The angle of the prism \( A = 75^\circ \) - The refractive index of the prism \( \mu = \sqrt{2} \) - The light ray is incident on the second face of the prism at the critical angle \( C \). ### Step 2: Calculate the Critical Angle ...
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