A ray of light is incident at small angle I on the surface of prism of small angle A and emerges normally from the oppsite surface. If the refractive index of the material of the prism is mu, the angle of incidence is nearly equal to

Options

A. `A//mu`
B. `A//2mu`
C. `muA`
D. `muA//2`

Answer

C

Explanation

Since the ray emerges normally, therefore `e=0.`
According to relation `A+delta=i+e` ,we get `i=A+delta` .
Here by `delta=(mu-1)A,` we get `i=muA`.