The angle of a prism is `60^(@)` and its refractive index is `sqrt(2)`. The angle of minimum deviation suffered by a ray of light in passing through it is

Options

A. About `20^(@)`
B. `30^(@)`
C. `60^(@)`
D. `45^(@)`

Answer

B

Explanation

`mu=(sin((A+delta_(m))/(2)))/(sin((A)/(2)))impliessqrt(2)mu=(sin((60+delta_(m))/(2)))/(sin((60)/(2)))`
`implies sqrt(2)xxsin 30 =sin((60+delta_(m))/(2))impliessin 45^(@)`
`=sin ((60+delta_(m))/(2))impliesd_(m)=30^(@)`