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The far point of a myopia eye is at 40 c...

The far point of a myopia eye is at `40 cm`. For removing this defect, the power of lens required will be

A

`40D`

B

`-4D`

C

`-2.5 D`

D

`0.25D`

Text Solution

Verified by Experts

The correct Answer is:
C
For myopic eye `f=-`(defected far point )
`impliesf=-40cmimpliesP=(100)/(-40)=-2.5D`
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