A simple telescope, consisting of an objective of focal length `60 cm` and a single eye lens of focal length `5 cm` is focused on a distant object is such a way that parallel rays comes out from the eye lens. If the object subtends an angle `2^(@)` at the objective, the angular width of the image.

Options

A. `10^(@)`
B. `24^(@)`
C. `50^(@)`
D. `1//6^(@)`

Answer

B

Explanation

Since `m=(f_(o))/(f_(e))`
Also `m=("Angle subtended by the image" )/("Angle subtended by the object")`
`:. (f_(o))/(f_(e))=(alpha)/(beta)impliesa=(f_(o)xxbeta)/(f_(e))=(60xx2)/(5)=24^(@)`