In a compound microscope the objective of `f_(o)` and eyepiece of `f_(e)` are placed at distance `L` such that `L` equals

Options

A. `f_(o)+f_(e)`
B. `f_(o)-f_(e)`
C. Much greater than `f_(o)` or `f_(e)`
D. Need not depend either value of focal lengths

Answer

C

Explanation

`L=v_(o)+u_(e)` and `v_(o)gt gtf_(o),u_(e)~=f_(e)`