For a prism of refractive index `1.732`, the angle of minimum deviation is equal to the angle of the prism. The angle of the prism is

Options

A. `80^(@)`
B. `70^(@)`
C. `60^(@)`
D. `50^(@)`

Answer

C

Explanation

`mu=(sin.(A+delta_(m))/(2))/(sin .(A)/(2))=(sin.(A+A)/(2))/(sin.(A)/(2))=(sin A)/(sin.(A)/(2))`
`=(2sin.(A)/(2)cos.(A)/(2))/(sin.(A)/(2))=2cos.(A)/(2)`
So, `sqrt(3)=2cos.(A)/(2)`
`implies(sqrt(3))/(2)=cos.(A)/(2)impliesA=60^(@)`