The kinetic energy of electron and proton is `10^(-32) J`. Then the relation between their de - Broglie wavelength is

Options

A. `lambda_(p) lt lambda_(e)`
B. `lambda_(p) gt lambda_(e)`
C. `lambda_(p) = lambda_(e)`
D. `lambda_(p) = 2lambda_(e)`

Answer

A

Explanation

By using `l = (h)/(sqrt(2 m E)) E = 10^(-32) J =` constant for both particles . Hence `lambda prop (1)/(sqrt(m))` Since `m_(p) gt m_(e)` So `lambda_(p) lt lambda_(e)`.