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What will be the ratio of de - Broglie w...

What will be the ratio of de - Broglie wavelengths of proton and `alpha` - particle of same energy ?

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The correct Answer is:
A
`lambda = (h)/(sqrt(2 m E)) rArr lambda prop (1)/(sqrt(m)) rArr (lambda_(p))/(lambda_(p)) sqrt((m_(a))/(m_(p))) = (2)/(1)`
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A2Z-DUAL NATURE OF RADIATION AND MATTER-Section D - Chapter End Test
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  20. From the figure describing photoelectric effect we may infer correctly...

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