The wavelength of de - Broglie wave is `2 mu m` , then its momentum is `( h = 6.63 xx 10^(-34 J-s)`

Options

A. `3.315 xx 10^(-28) kg - m//s`
B. `1.66 xx 10^(-28) kg - m//s`
C. `4.97 xx 10^(-28) kg-m//s`
D. `9.9 xx 10^(-28) kg - m//s`

Answer

A

Explanation

`lambda = (h)/(p) rArr p = (h)/(lambda) = (6.63 xx 10^(-34))/(2 xx 10^(-6))`
`= 3.31 xx 10^(-28) kg - m//sec`