The momentum of the photon of wavelength `5000 Å` will be

Options

A. `1.3 xx 10^(-27) kg - m//sec`
B. `1.3 xx 10^(-28) kg-m//sec`
C. `4 xx 10^(29) kg - m//sec`
D. `4 xx 10^(-18) kg - m//sec`

Explanation

To find the momentum of a photon with a wavelength of \(5000 \, \text{Å}\), we can follow these steps:

### Step-by-Step Solution:

1. **Convert Wavelength from Angstroms to Meters**:
\[ 1 \, \text{Å} = 10^{-10} \, \text{m} \]
Therefore,
\[ \lambda = 5000 \, \text{Å} = 5000 \times 10^{-10} \, \text{m} = 5 \times 10^{-7} \, \text{m} \]

2. **Use the Formula for Momentum of a Photon**:
The momentum \(P\) of a photon can be calculated using the formula:
\[ P = \frac{h}{\lambda} \]
where \(h\) is Planck's constant, approximately \(6.626 \times 10^{-34} \, \text{Js}\).

3. **Substitute the Values into the Formula**:
\[ P = \frac{6.626 \times 10^{-34} \, \text{Js}}{5 \times 10^{-7} \, \text{m}} \]

4. **Calculate the Momentum**:
\[ P = \frac{6.626 \times 10^{-34}}{5 \times 10^{-7}} = 1.3252 \times 10^{-27} \, \text{kg m/s} \]
Rounding to three significant figures, we get:
\[ P \approx 1.33 \times 10^{-27} \, \text{kg m/s} \]

### Final Answer:
The momentum of the photon with a wavelength of \(5000 \, \text{Å}\) is approximately \(1.33 \times 10^{-27} \, \text{kg m/s}\).

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