Energy of an quanta of frequency 10^(15)...

Energy of an quanta of frequency `10^(15) Hz` and `h = 6.6 xx 10^(-34) J - sec` will be

`6.6 xx 10^(-19) J`

`6.6 xx 10^(-12) J`

`6.6 xx 10^(-49) J`

`6.6 xx 10^(-41) J`

Text Solution

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The correct Answer is:

`E = hv = 6.6 xx 10^(-34) xx 10^(15) = 6.6 xx 10^(-19) J`

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