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Momentum of a photon of wavelength lambd...

Momentum of a photon of wavelength `lambda` is

A

`(h)/( lambda)`

B

Zero

C

`( h lambda)/( c^(2))`

D

`( h lambda)/(c )`

Text Solution

Verified by Experts

The correct Answer is:
A
Since `hv = mc^(2) `, hence `p = mc = (hv)/( c ) = (h)/(lambda)`
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