There are `n_(1)` photons of frequency `gamma_(1)` in a beam of light . In an equally energentic beam , there are `n_(2)` photons of frequency `gamma_(2)`. Then the correct relation is

Options

A. `(n_(1))/(n_(2)) = 1`
B. `(n_(1))/(n_(2)) = (gamma_(1))/(gamma_(2))`
C. `(n_(1))/(n_(2)) = (gamma_(2))/(gamma_(1))`
D. `(n_(1))/(n_(2)) = (gamma_(1)^(2))/(gamma_(2)^(2))`

Answer

C

Explanation

`E = nhv rArr v prop (1)/(n) rArr (n_(1))/(n_(2)) = (gamma_(2))/(gamma_(1))`.