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If the energy of the photon is increased...

If the energy of the photon is increased by a factor of `4` , then its momentum

A

Does not change

B

Decreases by a factor of `4`

C

Increases by a factor of `4`

D

Decreases by a factor of `2`

Text Solution

Verified by Experts

The correct Answer is:
C
`P = (h)/(lambda) , E = (hc )/(lambda) rArr E = Pc`.
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