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The ratio of the energy of a photon with...

The ratio of the energy of a photon with `lambda = 150 m` to that with `lambda = 300 m` is

A

`2`

B

`1//4`

C

`4`

D

`1//2`

Text Solution

Verified by Experts

The correct Answer is:
A
`E = (hc)/(lambda) rArr (E_(1))/(E_(2)) = (300)/(150) = (2)/(1)`
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