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The number of photons of wavelength 540 ...

The number of photons of wavelength `540 nm` emitted per second by an electric bulb of power `100 W` is (taking `h = 6 xx 10^(-34) sec`)

A

`100`

B

`1000`

C

`3 xx 10^(20)`

D

`3 xx 10^(18)`

Text Solution

Verified by Experts

The correct Answer is:
C
`P = (nhc)/(lambda t) rArr 100 = (n xx 6 xx 10^(-34) xx 3 xx 10^(8))/(540 xx 10^(-9) xx 1)`
`rArr n = 3 xx 10^(20)`
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