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The stopping potential V for photoelectr...

The stopping potential `V` for photoelectric emission from a metal surface is plotted along Y - axis and frequency `v` of incident light along X - axis . A straight line is obtained as shown . Planck's constant is given by

A

Slope of the line

B

Product of slope on the line and charge on the electron

C

Product of intercept along Y - axis and mass of the electron

D

Product of Slope and mass of electron

Text Solution

Verified by Experts

The correct Answer is:
B

`K_(max) = hv - hv_(0) rArr eV_(0) = hv - hv_(0) rArr V_(0) = (h)/( e) v - (hv_(0))/( e)`
Comparing this equation with `y = mx + c` , we get slope `m = (h)/( e) rArr h = m xx e`.
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Knowledge Check

  • A graph is plotted taking ""^(ul@)C along the Y - axis and of along the X - axis .It is a /an

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