In an experiment on photoelectric effect the frequency `f` of the incident light is plotted against the stopping potential `V_(0)`. The work function of the metal is given by ( e is the electronic charge)

Options

A. `OB xx e ` in eV
B. OB in Volt
C. OA in Volt
D. The slope of the line `AB`

Answer

A

Explanation

Using Einstein's equation , `V_(0) = ((h)/( e)) v - (W_(0))/( e )`
Comparing this equation with `y - mx + c`,
we get on `- V_(0)` axis as ` -(W_(0))/( e )`.
`rArr OB = (W_(0))/€ rArr W_(0) = OB xx e`