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If the work function of a metal is 'phi'...

If the work function of a metal is `'phi'` and the frequency of the incident light is `'v'`, there is no emission of photoelectron if

A

`v lt (phi)/(h)`

B

`v = (phi)/(h)`

C

`v gt (phi)/(h)`

D

`vge(phi)/(h)`

Text Solution

Verified by Experts

The correct Answer is:
A
For no emission of photoelectron , energy of incident light lt Work function `rArr hv lt phi rArr v lt (phi)/( h)`
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