When light of wavelength 300 nm (nanomet...

When light of wavelength `300 nm` (nanometre) falls on a photoelectric emitter , however light of `600 nm` wavelength is sufficient for creating photoemission . What is the ratio of the work functions of the two emitters ?

`1 : 2`

`2 :1`

`4 : 1`

`1 : 4`

Text Solution

Verified by Experts

The correct Answer is:

Work function ` = ( hc)/(lambda_(0))` , where `lambda_(0)` is threshold wavelength .
`:. (W_(01))/(W_(02)) = (lambda_(02))/(lambda_(01)) = (2)/(1)`

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