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What is the stopping potential when the ...

What is the stopping potential when the metal with work function `0.6 eV` is illuminated with the light of `2 eV` ?

A

`2.6 V`

B

`3.6 V`

C

`0.8 V`

D

`1.4 V`

Text Solution

Verified by Experts

The correct Answer is:
D
`V_(0) = ((E - W_(0)))/ ( e ) = (( 2eV - 0.6 eV))/( e ) = 1.4 V`
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