If the cathode - anode potential difference in an `X` - ray tube be `10^(5) V` , then the maximum energy of `X` - ray photon can be

Options

A. `10^(5) J`
B. `10^(5) MeV`
C. `10^(-1) MeV`
D. `10^(5) KeV`

Answer

C

Explanation

Since `lambda_(min) = (12375)/(V) Å = (12375)/(10^(5)) Å = 0.123 Å`
`E_(max) = ( hc) /(lambda_(min))`,
On putting the values . `E_(max) ~= 10^(-1) MeV`.