A potential difference of 42,000 "volts"...

A potential difference of `42,000 "volts"` is used in an `X` - ray tube to accelerate electrons . The maximum frequency of the `X` - radiations produced is

`10^(19) Hz`

`10^(18) Hz`

`10^(16) Hz`

`10^(20) Hz`

Text Solution

Verified by Experts

The correct Answer is:

`hv_(0) = eV :. V_(0) = (eV)/(h) = (1.6 xx 10^(-19) xx 42000)/(6.63 xx 10^(-34)) = 10^(19) Hz`

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