In X-ray tube , when the accelerating voltage `V` is halved, the difference between the wavelength of `K_(alpha)` line and minimum wavelength of continuous X-ray spectrum

Options

A. Remains constant
B. Becomes more than two times
C. Becomes half
D. Becomes less than two times

Answer

D

Explanation

`Delta lambda = lambda_(K_(alpha))- lambda_(min)` When `V` is halved `lambda_(min)` becomes two times but `lambda_(K_(alpha))` remains the same .
`:. Delta lambda' = lambda_(K_(alpha)) - 2 lambda_(min) = 2 (Delta lambda) - lambda_(K_(alpha))`
`:. Delta lambda' = 2 (Delta lambda)`