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The K(alpha) X-ray emission line of lung...

The `K_(alpha)` X-ray emission line of lungsten accurs at `lambda = 0.021 nm`. What is the energy difference between `K`and `L` levels in the atom?

A

`0.51 MeV`

B

`1.2 MeV`

C

`59 KeV`

D

`13.6 eV`

Text Solution

Verified by Experts

The correct Answer is:
C
`E_(K) - K_(L) = (hc)/( lambda)`
`((6.6 xx 10^(-34)) (3 xx 10^(8)))/((0.021 xx 10^(-9)) (1.6 xx 10^(-19))) eV = 59 keV`
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